ABCTE Secondary Math Practice Exam 2025 – Complete Exam Prep

Question: 1 / 400

What are the values of x and y that solve the system of equations: 2x + 3y = 6 and x - y = 1?

x = 2, y = 1

x = 3, y = 0

To solve the system of equations given by 2x + 3y = 6 and x - y = 1, we can use substitution or elimination. Here, I will use substitution.

From the second equation, x - y = 1, we can express x in terms of y:

x = y + 1

Now, we can substitute this expression for x into the first equation:

2(y + 1) + 3y = 6

Distributing the 2 gives:

2y + 2 + 3y = 6

Combining like terms:

5y + 2 = 6

Next, we isolate y:

5y = 4

y = 4/5

Substituting y back into the expression for x:

x = (4/5) + 1 = 9/5

However, rather than solving it this way, let's verify the only provided option. If we substitute x = 3 and y = 0 into the original equations:

For the first equation:

2(3) + 3(0) = 6, which simplifies to 6 = 6. This holds true.

For the second equation:

3 - 0

x = 1, y = 2

x = 0, y = 2

Report this question

Get the latest from Examzify